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Author Topic: Simple Analog Question.  (Read 7593 times)

Bobby

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Simple Analog Question.
« on: May 09, 2015, 02:39:53 PM »
Hello all!!

  I am still new to PLC programming and am working on my first project using a do-more plc. I have a 16 bit analog card in my rack. I understand that the resolution of that card is 65,536. My former training taught me that 0=0volts and 65,536=10volts for example. But with the do-more is shows the range being -32768 to +32767. Does that just mean the -32768 would read out a 0 volts and that +32767 would read out 10 volts? (or 5 depending on the settings I guess). Also if that is correct why do it like this? Is there a benefit that I do not see?


Thanks,

Bobby
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plcnut

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Re: Simple Analog Question.
« Reply #1 on: May 09, 2015, 03:36:35 PM »
It sounds like your module is set up for bi-polar (-5 to +5vdc). If you set it for uni-polar then it should be 0-65535.
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BobO

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Re: Simple Analog Question.
« Reply #2 on: May 09, 2015, 11:13:18 PM »
The analog data types, WX and WY, are signed by default. If you need 16 bit unipolar, you need to append the unsigned cast operator, e.g., WX0:U.
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LWgreys

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Re: Simple Analog Question.
« Reply #3 on: May 17, 2015, 07:09:45 PM »
Which analog module do you have?
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